Dec. 3, 2006
6:59 p.m.
Fredrik Lundh schrieb:
Ah, right; I misread his proposal as saying that m[:] should return [m[0]] + list(m.groups()) (rather, I expected that m.groups() would include m.group(0)).
match groups are numbered 1..N, not 0..(N-1), in both the API and in the RE syntax (and we don't have much control over the latter).
py> m = re.match("a(b)","ab") py> m.group(0) 'ab' py> m.group(1) 'b'
To answer your first question: it is clearly groups that you want to index, just as the .group() method indexes groups.
so what should len(m) do?
That's a question: should len be supported at all? If so, it's clear that len(m) == len(m[:]). Regards, Martin