18 May
2011
18 May
'11
2:19 p.m.
On Wed, May 18, 2011 at 2:21 PM, Victor Stinner <victor.stinner@haypocalc.com> wrote:
''.join(c for c in 'abc') and ''.join([c for c in 'abc']) do create a temporary c variable.
I'm not sure why you would encounter code like that in the first place. Surely any code of the form: ''.join(c for c in my_string) would just return my_string? Or am I missing something?
I heard about optimization in the AST tree instead of working on the bytecode. What is the status of this project?
Are you referring to issue11549? There was some related discussion [1] on python-dev about six weeks ago, but I haven't seen anything on the topic since then. Cheers, Nadeem [1] http://mail.python.org/pipermail/python-dev/2011-April/110399.html