Err, misread. How do you know that range is a builtin you're thinkingOn Fri, Dec 31, 2010 at 12:00 PM, Maciej Fijalkowski <fijall@gmail.com> wrote:
>> OK, but is it mandatory? For example, in the above code, I can unroll the
>> loop because I found that range is the usual built-in, 5 is a low-enough
>> constant,
>
> How do you know xrange is xrange and not something else?
>
> Cheers,
> fijal
>
about and not some other object?
Cheers,
fijal