11 Oct
2016
11 Oct
'16
7:32 a.m.
But the sort mutates F...does the setup get executed each time? I thought it's just at the beginning. So then F gets mutated (sorted) and subsequent sorts time wrong. On Tue, Oct 11, 2016, 7:51 AM Paul Moore
Right, that sounds good, but there's just one thing I don't understand that's keeping me from using it. Namely, I would define a benchmark list L in my setup, and then I would have code="F=FastList(L);F.fastsort()". The problem here is I'm measuring the constructor time along with the sort time, right, so wouldn't that mess up the benchmark? Or does timeit separate
On 11 October 2016 at 14:04, Elliot Gorokhovsky
wrote: the times?
That would mess up your times. Put F=FastList(L) in your setup.
Paul