Re: [Python-Dev] A wart which should have been repaired in 3.0?

On Tue, 30 Dec 2008 at 21:30, rdmurray@bitdance.com wrote:

On Tue, 30 Dec 2008 at 17:51, Phillip J. Eby wrote:

...

At 02:32 PM 12/30/2008 -0800, Scott David Daniels wrote:

...

More trouble with the "just take the dirname":

  paths = ['/a/b/c', '/a/b/d', '/a/b']
  os.path.dirname(os.path.commonprefix([
                      os.path.normpath(p) for p in paths]))

give '/a', not '/a/b'.

...because that's the correct answer.

But not the answer that is wanted.

So the challenge now is to write a single expression that will yield '/a/b' when passed the above paths list, and also produce '/a/b' when passed the following paths list:

paths = ['/a/b/c', '/a/b/cd']

Sorry, now I see what you are saying: that in '/a/b' the 'b' is the filename. Clearly that wasn't what I intuitively expected our notional 'commonpathprefix' command to produce, for whatever that is worth :)

--RDM