Giovanni Bajo wrote:
Yes but:
a = [] for i in range(10): ... a.append(lambda: i) ... print [x() for x in a] [9, 9, 9, 9, 9, 9, 9, 9, 9, 9]
This subtle semantic of lambda is quite confusing, and still forces people to use the "i=i" trick.
If you'd like each function instance to have a separate closure scope, then *give* each function a separate closure scope, instead of making them all share the same one the way you have above:
def make_f(i): ... def f(): ... return i ... return f ... a = [] for i in range(10): ... a.append(make_f(i)) ... print [x() for x in a] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
Cheers, Nick. -- Nick Coghlan | ncoghlan@gmail.com | Brisbane, Australia --------------------------------------------------------------- http://www.boredomandlaziness.org