Here, `seq1 == seq2` produces a boolean array (i.e., an array of boolean values).
hth, Alan Isaac


On 12/22/2020 2:28 PM, Ivan Pozdeev via Python-Dev wrote:
>
> You sure about that? For me, bool(np.array) raises an exception:
>
> In [12]: np.__version__ Out[12]: '1.19.4'
>
> In [11]: if [False, False]==np.array([False, False]): print("foo") <...> ValueError: The truth value of an array with more than one element is ambiguous.
> Use a.any() or a.all()
>
>



> On 22.12.2020 21:52, Alan G. Isaac wrote:
>> The following test fails because because `seq1 == seq2` returns a (boolean) NumPy array whenever either seq is a NumPy array.
>>
>> import unittest import numpy as np unittest.TestCase().assertSequenceEqual([1.,2.,3.], np.array([1.,2.,3.]))
>>
>> I expected `unittest` to rely only on features of a `collections.abc.Sequence`, which based on https://docs.python.org/3/glossary.html#term-sequence, I
>> believe are satisfied by a NumPy array. Specifically, I see no requirement that a sequence implement __eq__ at all much less in any particular way.
>>
>> In short: a test named `assertSequenceEqual` should, I would think, work for any sequence and therefore (based on the available documentation) should not
>> depend on the class-specific implementation of __eq__.
>>
>> Is that wrong?
>>
>> Thank you, Alan Isaac _______________________________________________ Python-Dev mailing list -- python-dev@python.org To unsubscribe send an email to
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