The iterator is not revaluated, instead, it is constructing a single iterator, in this case a list_iterator. The list_iterator looks at the underyling list to know how to iterate so when you mutate the underlying list, the list_iterator sees that. This does not mee the expression used to generate the iterator was re-evaluated.

On Wed, Aug 5, 2015 at 11:25 AM, John Doe <z2911@bk.ru> wrote:
To pass by reference or by copy of - that is the question from hamlet. ("hamlet" - a community of people smaller than a village python3.4-linux64)

xlist = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
i = 0
for x in xlist:
    print(xlist)
    print("\txlist[%d] = %d" % (i, x))
    if x%2 == 0 :
        xlist.remove(x)
    print(xlist, "\n\n")
    i = i + 1

So, catch the output and help me, PLEASE, improve the answer:
Does it appropriate ALWAYS REevaluate the terms of the expression list in FOR-scope on each iteration?
But if I want to pass ONCE a copy to FOR instead of a reference (as seen from an output) and reduce unreasonable reevaluation, what I must to do for that?
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