+1 to this. On Sun, May 11, 2008 at 6:23 PM, Scott Dial <scott+python-dev@scottdial.com> wrote:
Brett Cannon wrote:
Taking a new argument that has a default shouldn't be an issue. +1 from me. I assume it is just going to start the count at that number, not advance the iterable to that point, right?
I wonder if it would be best for it to be a keyword-only argument. So many of the utility functions on iterables are foo(*iterables) that I might be inclined to think enumerate(foo, bar) is equivalent to enumerate(chain(foo, bar)), but enumerate(foo, start=bar) is pretty obvious. And if you consider that the enumeration is prepended to the values of foo, enumerate(foo, bar) is "backwards." Just saying..
-Scott
-- Scott Dial scott@scottdial.com scodial@cs.indiana.edu
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