May 19, 2007
5:17 p.m.
* New method (proposed by Shane Holloway): s1.isdisjoint(s2). Logically equivalent to "not s1.intersection(s2)" but has an early-out if a common member is found.
[MvL]
I'd rather see iterator versions of the set operations.
Interesting idea. I'm not sure I see how to make it work. If s|t returned an iterator, then how would s|t|u work? Are you proposing lazy evaluation of unions, intersections, and differences? Raymond