On 22.12.2020 21:52, Alan G. Isaac wrote:
The following test fails because because `seq1 == seq2` returns a (boolean) NumPy array whenever either seq is a NumPy array.
You sure about that? For me, bool(np.array) raises an exception: In [12]: np.__version__ Out[12]: '1.19.4' In [11]: if [False, False]==np.array([False, False]): print("foo") <...> ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()
import unittest import numpy as np unittest.TestCase().assertSequenceEqual([1.,2.,3.], np.array([1.,2.,3.]))
I expected `unittest` to rely only on features of a `collections.abc.Sequence`, which based on https://docs.python.org/3/glossary.html#term-sequence, I believe are satisfied by a NumPy array. Specifically, I see no requirement that a sequence implement __eq__ at all much less in any particular way.
In short: a test named `assertSequenceEqual` should, I would think, work for any sequence and therefore (based on the available documentation) should not depend on the class-specific implementation of __eq__.
Is that wrong?
Thank you, Alan Isaac _______________________________________________ Python-Dev mailing list -- python-dev@python.org To unsubscribe send an email to python-dev-leave@python.org https://mail.python.org/mailman3/lists/python-dev.python.org/ Message archived at https://mail.python.org/archives/list/python-dev@python.org/message/6Z43SU2R... Code of Conduct: http://python.org/psf/codeofconduct/
-- Regards, Ivan