Re: [Python-Dev] PEP 418: Add monotonic clock

That's simple clear and explicit: try_monotic() tries to use the monotic clock if it can, but falls back to time.time() rather than failing entirely if no monotonic clock is available.

I renamed time.steady() to time.try_monotonic() in the PEP. It's a temporary name until we decide what to do with this function. I also changed it to fallback to time.hires() if time.monotonic() is not available or failed. Victor