Nick Coghlan wrote:
Interestingly, with this approach, "for dummy in my_resource()" would still wrap the block of code in the entrance/exit code (because my_resource *is* a generator), but it wouldn't get the try/finally semantics.
An alternative would be to replace the 'yield None' with a 'break' or 'continue', and create an object which supports the resource protocol and NOT the iterator protocol. Something like:
def my_resource(): print "Hi!" # Do entrance code continue # Go on with the contents of the 'with' block print "Bye!" # Do exit code
(This is currently a SyntaxError, so it isn't ambiguous in any way)
Oh, it is ambiguous, as soon as you insert a for/while statement in your resource function and want to call continue in there. Other than that, it's very neat. Maybe "yield" alone (which is always a SyntaxError) could be used. Reinhold -- Mail address is perfectly valid!