Am 28.12.2010 18:24, schrieb Benjamin Peterson:
2010/12/28 Lukas Lueg <lukas.lueg@googlemail.com>:
Consider the following code:
def foobar(x): for i in range(5): x[i] = i
The bytecode in python 2.7 is the following:
2 0 SETUP_LOOP 30 (to 33) 3 LOAD_GLOBAL 0 (range) 6 LOAD_CONST 1 (5) 9 CALL_FUNCTION 1 12 GET_ITER >> 13 FOR_ITER 16 (to 32) 16 STORE_FAST 1 (i)
3 19 LOAD_FAST 1 (i) 22 LOAD_FAST 0 (x) 25 LOAD_FAST 1 (i) 28 STORE_SUBSCR 29 JUMP_ABSOLUTE 13 >> 32 POP_BLOCK >> 33 LOAD_CONST 0 (None) 36 RETURN_VALUE
Can't we optimize the LOAD_FAST in lines 19 and 25 to a single load and put the reference twice on the stack?
Yes. Would it be useful? Unlikely.
Is it tricky to get all the corner cases right? Very probably :) Georg