Dec. 3, 2006
9:01 p.m.
Steve Holden schrieb:
Precisely. But your example had only one group "(b)" in it, which is retrieved using m.group(1). So the subgroups are numbered starting from 1 and subgroup 0 is a special case which returns the whole match.
I know what the Zen says about special cases, but in this case the rules were apparently broken with impunity.
Well, the proposal was to interpret m[i] as m.group(i), for all values of i. I can't see anything confusing with that. Regards, Martin