Re: [Python-Dev] Add a frozendict builtin type

01.03.12 01:52, Victor Stinner написав(ла):

Problem: if you implement a frozendict type inheriting from dict in Python, it is still possible to call dict methods (e.g. dict.__setitem__()). To fix this issue, pysandbox removes all dict methods modifying the dict: __setitem__, __delitem__, pop, etc. This is a problem because untrusted code cannot use these methods on valid dict created in the sandbox.

You can redefine dict.__setitem__. oldsetitem = dict.__setitem__ def newsetitem(self, value): # check if self is not frozendict ... oldsetitem(self, value) .... dict.__setitem__ = newsetitem