Hi all,

Apologies in advance; I'm not a regular, and this may have been
handled already (but I couldn't find it when searching).

I've been using the new async/await functionality (congrats again to
Yury on getting that through!), and I'd like to get a stack trace
between the place at which blocking occurs and the outer co-routine.

For example, consider this code:

"""
async def a():
    await b()

async def b():
    await switch()

@types.coroutine
def switch():
    yield

coro_a = a()
coro_a.send(None)
"""

At this point I'd really like to be able to somehow get a stack trace
similar to:

test.py:2
test.py:4
test.py:9

Using the gi_frame attribute of coro_a, I can get the line number of
the outer frame (e.g.: line 2), but from there there is no way to
descend the stack to reach the actual yield point.

I thought that perhaps the switch() co-routine could yield the frame
object returned from inspect.currentframe(), however once that
function yields that frame object has f_back changed to None.

A hypothetical approach would be to work the way down form the
outer-frame, but that requires getting access to the co-routine object
that the outer-frame is currently await-ing. Some hypothetical code
could be:

"""
def show(coro):
    print("{}:{}".format(coro.gi_frame.f_code.co_filename,
coro.gi_frame.f_lineno))
    if dis.opname[coro.gi_code.co_code[coro.gi_frame.f_lasti + 1]] ==
'YIELD_FROM':
        show(coro.gi_frame.f_stack[0])
"""

This relies on the fact that an await-ing co-routine will be executing
a YIELD_FROM instruction. The above code uses a completely
hypothetical 'f_stack' property of frame objects to pull the
co-routine object which a co-routine is currently await-ing from the
stack. I've implemented a proof-of-concept f_stack property in the
frameobject.c just to test out the above code, and it seems to work.

With all that, some questions:

1) Does anyone else see value in trying to get the stack-trace down to
the actual yield point?
2) Is there a different way of doing it that doesn't require changes
to Python internals?
3) Assuming no to #2 is there a better way of getting the information
compared to the pretty hacking byte-code/stack inspection?

Thanks,

Ben
_______________________________________________
Python-Dev mailing list
Python-Dev@python.org
https://mail.python.org/mailman/listinfo/python-dev
Unsubscribe: https://mail.python.org/mailman/options/python-dev/jaivishkothari10104733%40gmail.com