If you read the language reference for augmented arithmetic assignment, you will note that it essentially says, "call __i<op>__, and if that doesn't work call as if you were doing a <op> b". Unfortunately it appears **= does not follow the rule of falling back on the binary arithmetic expression semantics. I have a GitHub gist with demonstration code that shows this happening in both 3.8 and master (https://gist.github.com/brettcannon/fec4152857e0ed551b4da515dc63e580). This was reported in https://bugs.python.org/issue38302, although initially it didn't cover __pow__, only __rpow__ being skipped.

This appears to happen because the opcode  for **= calls PyNumber_InPlacePower() (https://github.com/python/cpython/blob/802726acf6048338394a6a4750835c2cdd6a947b/Objects/abstract.c#L1159) which calls ternary_op for __ipow__ or __pow__ depending on which is defined, but will never try both (https://github.com/python/cpython/blob/802726acf6048338394a6a4750835c2cdd6a947b/Objects/abstract.c#L849). All of the other augmented arithmetic assignment operators have a special binary_iop() function to call which takes care of the fallback logic, so no other augmented arithmetic assignments appear to have this problem (I tested them all regardless).

I think there are two options to fixing this:

1. Add a note to the data model that **= is special and does not fall back (obviously the most backwards-compatible)

2. Fix **= (which makes sense from a language consistency perspective)

Personally, my vote is for #2 as I don't want to have to remember that **= is somehow special compared to all other augmented assignments. I also don't think the backwards-compatibility risk is at all large since the semantics of turning `a **= b` into `a = a ** b` shouldn't really be different.

P.S. Why are some of the PyNumber_InPlace*() functions handwritten while others are defined using a macro which mirrors the handwritten ones? Just something I noticed while investigating this.

_______________________________________________
Python-Dev mailing list -- python-dev@python.org
To unsubscribe send an email to python-dev-leave@python.org
https://mail.python.org/mailman3/lists/python-dev.python.org/
Message archived at https://mail.python.org/archives/list/python-dev@python.org/message/MJTHPFSHGH7RIEKXQKYUBHCZBW3T3JTR/
Code of Conduct: http://python.org/psf/codeofconduct/