Mailman 3 Strange message error in socket.sendto() exception - Python-Dev

Aug. 20, 2011

      Python 3.2 (r32:88445, Mar 25 2011, 19:28:28)
[GCC 4.5.2] on linux2
...
...
...
import socket
s = socket.socket()
print(s.sendto.__doc__)
sendto(data[, flags], address) -> count
...
s.sendto(b'data', ('localhost', 3))
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
socket.error: [Errno 32] Broken pipe
This is ok, I expected this. However, note what happens if I send unicode:
...
...
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s.sendto('data', ('localhost', 3))
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: sendto() takes exactly 3 arguments (2 given)
An error regarding the argument quantity? what?

Furthermore, where this message comes from? I tried to find, but the
only hint I get is that it could come from
"./Modules/_ctypes/_ctypes.c"... are we using ctypes to access socket
methods? it's strange, because "sendto" is defined in socketmodule.c.

Ideas? Thanks!

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Strange message error in socket.sendto() exception

Facundo Batista

Antoine Pitrou

Vinay Sajip

Antoine Pitrou

Vinay Sajip

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