hex() and oct() still include the trailing L - change this in 2.6?
9 Nov
2007
9 Nov
'07
2:05 a.m.
I thought the hell of stripping trailing Ls off of stringed numbers was gone but it appears that the hex() and oct() builtins still leave the trailing 'L' on longs: Python 2.6a0 (trunk:58846M, Nov 4 2007, 15:44:12) [GCC 4.1.2 (Ubuntu 4.1.2-0ubuntu4)] on linux2 Type "help", "copyright", "credits" or "license" for more information.
x = 0xffffffffc10025be x 18446744072652596670L str(x) '18446744072652596670' hex(x) '0xffffffffc10025beL' '0x%x' % (x) '0xffffffffc10025be' oct(x) '01777777777770100022676L'
This appears to be fixed in py3k (as there is no longer an int/long to distinguish). Can we at least get rid of the annoying L in 2.6? -gps
6005
Age (days ago)
6005
Last active (days ago)
2 comments
3 participants
participants (3)
-
Brett Cannon
-
Gregory P. Smith
-
Guido van Rossum