I think you cheated a little in your cut-and-paste.  `student_by_school` is not defined in the code you've shown.  What you *did* define, `student_school_list` doesn't give you what you want if you use `defaultdict(list,student_school_list)`.

I thought for a moment I might just use:

[(b,a) for a,b in student_school_list]

But that's wrong for reasons that are probably obvious to everyone else.  I'm not really sure what `student_by_school` could possibly be to make this work as shown.

On Thu, Jun 28, 2018 at 8:13 PM Chris Barker via Python-ideas <python-ideas@python.org> wrote:
In [97]: student_school_list
Out[97]: 
[('Fred', 'SchoolA'),
 ('Bob', 'SchoolB'),
 ('Mary', 'SchoolA'),
 ('Jane', 'SchoolB'),
 ('Nancy', 'SchoolC')]

In [98]: result = defaultdict(list, student_by_school)

In [99]: result.items()
Out[99]: dict_items([('SchoolA', ['Fred', 'Mary']), ('SchoolB', ['Bob', 'Jane']), ('SchoolC', ['Nancy'])])

So: <small voice> never mind </small voice>

-CHB

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