On Sun, Feb 27, 2011 at 10:19 PM, Stephen J. Turnbull <stephen@xemacs.org>wrote:
def multisplit (source, char1, char2): ... return re.split("".join(["[",char1,char2,"]"]),source)
actually you need re.escape there in case one of the characters is \ or ]. And if remembering [...] is hard using | makes this a bit more general (accepting multi-character separators) def multisplit(source, *separators): return re.split('|'.join([re.escape(t) for t in separators]), source) multisplit(s, '\r\n', '\r', '\n') Bonus points if you see the problem with the above. Correct code below spoiler space . . . . . . . . . . . The problem is that an |-separated regex matches in order, so if a longer separator appears after a shorter one, the shorter one will take precedence. def multisplit(source, *separators): return re.split('|'.join([re.escape(t) for t in sorted(separators, key=len, reverse=True)]), source)