On Sun, Feb 27, 2011 at 10:19 PM, Stephen J. Turnbull
<stephen@xemacs.org> wrote:
def multisplit (source, char1, char2):
... return re.split("".join(["[",char1,char2,"]"]),source)
actually you need re.escape there in case one of the characters is \ or ]. And if remembering [...] is hard using | makes this a bit more general (accepting multi-character separators)
def multisplit(source, *separators):
return re.split('|'.join([re.escape(t) for t in separators]), source)
multisplit(s, '\r\n', '\r', '\n')
Bonus points if you see the problem with the above. Correct code below spoiler space
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The problem is that an |-separated regex matches in order, so if a longer separator appears after a shorter one, the shorter one will take precedence.
def multisplit(source, *separators):
return re.split('|'.join([re.escape(t) for t in
sorted(separators, key=len, reverse=True)]), source)