June 1, 2011
9:41 a.m.
On Tue, May 31, 2011 at 11:09 PM, Jacob Holm <jh@improva.dk> wrote:
x = 1
def f(): # The next statement uses the global x x += 1 x = 2 # From here, you have a local x
Specifically, the "x = 2" statement (and the lack of a nonlocal statement) forces x to be local throughout the function, and the "x += 1" statement then tries to read the local "x" and fails.
Yes, Jacob has got exactly what I was proposing. x += 1; x = 2 should continue to fail, since there would be a = statement in the function body in that case. -- Carl