On 1/5/19 7:38 PM, Simon wrote:
I was writing some python code earlier, and I noticed that in a code that looks somwhat like this one :
try: i = int("string") print("continued on") j = int(9.0) except ValueError as e: print(e)
"invalid literal for int() with base 10: 'string'"
this code will handle the exception, but the code in the try block will not continue.
I propose to be able to use the continue keyword to continue the execution of the try block even when an error is handled. The above could then be changed to :
try: i = int("string") print("continued on") j = int(9.0) except ValueError as e: print(e) continue
"invalid literal for int() with base 10: 'string'" "continued on"
How would you tell it where to continue? Why would it be the next statement? If you want that then you just need to do it like: try: i = int("string") except ValueError as e: print(e) print("continued on") j = int(9.0) i.e. the try block is the program segment that either executes successful, or your exception routine recovers from the error and sets things up to continue from there. -- Richard Damon