If you mark constant.DEBUG as constant and compile your project with astoptimizer, enable_debug has no effect (if it was compiled with DEBUG=False). So only use it if DEBUG will not be changed at runtime. It cannot be used if your users might run your applucation in debug mode. To compare it to the C language, DEBUG would be a #define and astoptimizer can be see as a preprocessor. Victor Le 30 déc. 2012 11:59, "Stefan Behnel" <stefan_ml@behnel.de> a écrit :
Victor Stinner, 30.12.2012 11:42:
My astoptimizer provides tools to really *remove* debug at compilation, so the overhead of the debug code is just null.
You can for example declare your variable project.config.DEBUG as constant with the value 0, where project.config is a module. So the if statement in "from project.config import DEBUG ... if DEBUG: ..." will be removed.
How would you know at compile time that it can be removed? How do you handle the example below?
Stefan
## constants.py
DEBUG = False
## enable_debug.py
import constants constants.DEBUG = True
## test.py
import enable_debug from constants import DEBUG
if DEBUG: print("DEBUGGING !")
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