Dear Masklinn,

thanks for your suggested solution.

I know all of these, but
1) it is not as elegant or short
2) why does unpacking not work syntactically the same as for the function parameters?
It seems a natural extension that appears not to have a syntactic conflict.  If it is not even a necessity for consistency.

So, the point is not that something like
[0,*x,0,*y,0]
can't be done in other ways, but that it can't be done in a neat way.

-Alexander

On 12/15/2011 11:27 AM, Masklinn wrote:

On 2011-12-15, at 17:26 , Alexander Heger wrote:

Or is there a way of doing this that in a similarly compact and
obvious way I did not yet discover?

If the list is uniform, you can flatten a single level by using `itertools.chain`:

    >>>  import itertools
    >>>  x = [1,2,3]
    >>>  y = itertools.chain.from_iterable([[0], x])
    >>>  list(y)
    [0, 1, 2, 3]
    >>>  # alternatively
    ... y = list(itertools.chain([0], x))
    >>>  y
    [0, 1, 2, 3]
    >>>

I know of no "better" way to do it at the moment, apart from using slice-assignment with a *stop* bound of 0:

    >>>  y = [0, 0]
    >>>  y[1:0] = x
    >>>  y
    [0, 1, 2, 3, 0]

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