Jan. 21, 2009
2:55 p.m.
Arnaud Delobelle schrieb:
How about this?
from itertools import * def fixlen(iterable, len, item=None): ... return islice(chain(iterable, repeat(item)), len) ... list(fixlen([1, 2, 3], 5)) [1, 2, 3, None, None]
I like this. Maybe an addition to itertools? +1