On Wed, Oct 3, 2018 at 9:29 AM Anders Hovmöller boxed@killingar.net wrote:
foo(=a, =1+bar)
Unfortunately, that won't help with Jonathan's inital example expression "big_array[5:20]" as it's not a valid keyword.
I didn't understand that. The example you are referring to is print('big_array[5:20] =', big_array[5:20])
Nothing is a keyword in that example or in my example. My suggestion is that we could do: my_func(=big_array[5:20])
And it would be compile time transformed into my_func(**{'big_array[5:20]': big_array[5:20]})
and then my_func is just a normal function:
def my_func(**kwargs): Whatever
You're right, that case will work. I was thinking of
In [1]: foo(a+b=1) File "<ipython-input-1-61f24dcb4c20>", line 1 foo(a+b=1) ^ SyntaxError: keyword can't be an expression