I think this is a great idea, but I would not want to introduce a new keyword. How about
foo is in bar = hasattr(foo,bar) foo is not in bar = not hasattr(foo,bar)
But there are other common checks I do all the time that I would really like to have shortcuts for. Here are ways to do them without new keywords:
foo is class bar = isinstance(foo,bar) foo is from bar = issubclass(foo,bar) foo is with bar = type(foo) == type(bar)
Can we make an exception to the moratorium, just for today?
--- Bruce http://www.vroospeak.com
On Thu, Apr 1, 2010 at 8:15 AM, Robert Madole firstname.lastname@example.org wrote:
So I just wrote my 1-gazillionth "if hasattr('method', my_object):" and wanted badly to write this.
if 'method' on my_object:
I'm not the most experienced Python user, but as far as I can tell hasattr is the preferred way of checking if a method exists.
Please correct me if there is a better way, otherwise I'd like to see what everyone thinks about an "on" statement being added to the Python language.
Rob Madole _______________________________________________ Python-ideas mailing list Pythonemail@example.com http://mail.python.org/mailman/listinfo/python-ideas