On Wed, September 26, 2007 10:42 pm, Terry Jones wrote:
What's the most compact way to repeatedly call a function on a list without accumulating the results?
While I can accumulate results via
a = [f(x) for x in mylist]
or with a generator, there doesn't seem to be a way to do this without accumulating the results. I guess I need to either use the above and ignore the result, or use
for x in mylist: f(x)
I run into this need quite frequently. If I write
[f(x) for x in mylist]
with no assignment, will Python notice that I don't want the accumulated results and silently toss them for me?
A possible syntax change would be to allow the unadorned
f(x) for x in mylist
And raise an error if someone tries to assign to this.
If you want to do it like this, why not do it explicitly: def exhaust(iterable): for i in iterable: pass Then you can write: exhaust(f(x) for x in mylist) Done! -- Arnaud