Lambda functions that have a single parameter are a common thing, e.g. for "key" functions: `sorted(items, key=lambda x: x['key'])`. For these cases however, the rather long word "lambda" together with the repetition of the parameter name, results in more overhead than actual content (the `x['key']`) and thus makes it more difficult to read. This is also a difficulty for `map` and `filter` for example where there's lots of visual overhead when using a lambda function and hence it's difficult to read: `filter(lambda x: x > 0, items)` or `map(lambda x: f'{x:.3f}', items)`. Hence the proposal is to add a new syntax via the new token `?`. For the examples above: * `sorted(items, key=?['key'])` * `filter(? > 0, items)` * `map(f'{?:.3f}', items)` The rules are simple: whenever the token `?` is encountered as part of an expression (at a position where a name/identifier would be legal), the expression is replaced by a lambda function with a single parameter which has that expression as a return value, where any instances of `?` are replaced by the name of that single parameter. For example: * `?['key']` translates to `lambda x: x['key']` * `? > 0` translates to `lambda x: x > 0` * `f'{?:.3f}'` translates to `lambda x: f'{x:.3f}'` * `?*?` translates to `lambda x: x*x` With the difference that the replacement function would use an unnamed parameter, i.e. not shadowing any names from outer scopes. So `? * x` would use `x` from enclosing scopes, not as the lambda parameter. Regarding operator precedence, the rules would be similar as for lambda functions, i.e. it will include as much in the expression as it would for a lambda function. To find more example use cases, I used `grep -rnE 'lambda [_a-zA-Z][_a-zA-Z0-9]*:' Lib/` on the CPython standard library to find single parameter lambda functions and there are various results coming up (although not all are applicable, e.g. because they return a constant value). I'll include a few examples below, but the actual list is much longer: ``` modes[char] = max(items, key=lambda x: x[1]) modes[char] = max(items, key=?[1]) # proposed new syntax obj = unwrap(obj, stop=(lambda f: hasattr(f, "__signature__"))) obj = unwrap(obj, stop=hasattr(?, "__signature__")) s = re.sub(r"-[a-z]\b", lambda m: m.group().upper(), s) s = re.sub(r"-[a-z]\b", ?.group().upper(), s) members.sort(key=lambda t: (t[1], t[0])) members.sort(key=(?[1], ?[0])) ``` Of course, there is no requirement to use `?` as the token, it could be any other character that's currently not used by Python, i.e. `$` or `!` would be possible too.