Does it make sense to draw some sort of parallel between next(myiterator, default="whatever") and mylist.pop(default="whatever")? They exhaust the iterator/list then start emitting the default argument (if provided).
31.10.18 13:08, Antoine Pitrou пише:
> +1 from me. dict.pop() already has an optional default. This is a
> straight-forward improvement to the API and no Python programmer will
> be surprised.
list.pop() corresponds two dict methods. With argument it corresponds
dict.pop(). But there are differences: dict.pop() called repeatedly with
the same key will raise an error (or return the default), while
list.pop() will likely return other item. Without argument it
corresponds dict.popitem() which doesn't have an optional default.
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