On Fri, May 10, 2013 at 7:08 PM, Alexander Belopolsky <alexander.belopolsky@gmail.com> wrote:
Does this earn a point?

x = (+ 'foo\n'

     + 'bar\n'
     + 'baz\n'
    )

Plus doesn't make sense as a unary operator on strings. 

x = ('foo\n' +
     'bar\n' + 
     'baz\n' +
     '')

This would work.