On Apr 23, 2012, at 9:52 AM, Steven D'Aprano wrote:
However, the discoverability of this solution is essentially zero
def powerset(iterable):
"powerset([1,2,3]) --> () (1,) (2,) (3,) (1,2) (1,3) (2,3) (1,2,3)"
s = list(iterable)
return chain.from_iterable(combinations(s, r) for r in range(len(s)+1))
the itertools can be readily combined to build new tools.