Jan. 6, 2019
12:38 a.m.
I was writing some python code earlier, and I noticed that in a code that looks somwhat like this one : try: i = int("string") print("continued on") j = int(9.0) except ValueError as e: print(e)
"invalid literal for int() with base 10: 'string'"
this code will handle the exception, but the code in the try block will not continue. I propose to be able to use the continue keyword to continue the execution of the try block even when an error is handled. The above could then be changed to : try: i = int("string") print("continued on") j = int(9.0) except ValueError as e: print(e) continue
"invalid literal for int() with base 10: 'string'" "continued on"