try:

        i = int("string")

        print("continued on")

        j = int(9.0)

    except ValueError as e:

        print(e)

>>> "invalid literal for int() with base 10: 'string'"

this code will handle the exception, but the code in the try block will not continue.

I propose to be able to use the continue keyword to continue the execution of the try block even when an error is handled. The above could then be changed to :

>>> "continued on"