Rather: assert lower <= upper And apologies if this has been requested before. My search turned up nothing. On Saturday, July 30, 2016 at 5:57:53 PM UTC-4, Neil Girdhar wrote:
It's common to want to clip (or clamp) a number to a range. This feature is commonly needed for both floating point numbers and integers:
http://stackoverflow.com/questions/9775731/clamping-floating-numbers-in-pyth...
http://stackoverflow.com/questions/4092528/how-to-clamp-an-integer-to-some-r...
There are a few approaches:
* use a couple ternary operators (e.g. https://github.com/scipy/scipy/pull/5944/files line 98, which generated a lot of discussion) * use a min/max construction, * call sorted on a list of the three numbers and pick out the first, or * use numpy.clip.
Am I right that there is no *obvious* way to do this? If so, I suggest adding math.clip (or math.clamp) to the standard library that has the meaning:
def clip(number, lower, upper): return lower if number < lower else upper if number > upper else number
This would work for non-numeric types so long as the non-numeric types support comparison. It might also be worth adding
assert lower < upper
to catch some bugs.
Best,
Neil