Le 08/03/17 à 23:30, Chris Angelico a écrit :
On Thu, Mar 9, 2017 at 9:23 AM, Brice PARENT <contact@brice.xyz> wrote:
Would those 2 dicts be equal ? d1 = dict(default=5) d2 = {'default': 5} Easy to find out:
d1 = dict(default=5) d2 = {'default': 5} d1 == d2 True
ChrisA That's my point... If they are equal, it clearly means that the declaration of d1 is *not* declaring a defaultdict right now, and is a valid syntax. So the behaviour would have to be changed, which would make legacy code erroneous in such a case.
But a possible workaround, is if we used the first positional argument of dict() as the default value. As right now it doesn't accept positional arguments (or at least if they are not iterable, which complicates a bit the thing), we could allow a syntax like : d = dict([default, ][*args, ]**kwargs) where default is a callable, *args made of iterables, and kwargs any kwargs.