I notice you said &quot;args&quot; not &quot;arg&quot;. How would you parse foo(x, y -&gt; x + y)? Even if the compiler can parse it, how about the human reading the code?<br><br>If lambda wasn&#39;t already there, I could see using (args) -&gt; expr syntax but I think there shouldn&#39;t be two ways to do something so simple.<br>

<br>If you really want a shorter syntax, the obvious choice is foo(ëx, y: x + y).<br><br>--- Bruce<br><br><br><div class="gmail_quote">On Fri, Aug 7, 2009 at 5:49 PM, Greg Ewing <span dir="ltr">&lt;<a href="mailto:greg.ewing@canterbury.ac.nz">greg.ewing@canterbury.ac.nz</a>&gt;</span> wrote:<br>

<blockquote class="gmail_quote" style="border-left: 1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;">My suggestion for a lightweight lambda syntax is<br>
<br>
  args -&gt; expr<br>
<br>
Examples:<br>
<br>
  map(x -&gt; x + 5, something)<br>
<br>
  d = defauldict(-&gt;[])<br>
<br>
-- <br><font color="#888888">
Greg</font><div><div></div><div class="h5"><br>
<br>
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