Jan. 24, 2015
1:56 a.m.
(But I wonder - wouldn't it work better with a "symmetrical" close-to function? That's probably a question for Chris.)
Well, you usually use Newton's algorithm to find the zero of a function, so in that case, you'd want an absolute comparison. But it's pretty common to do a simple iterative solution where you check convergence by seeing if the new solution is close to the previous solution, in which case, a symmetric test would probability be better, but the asymmetric one would be fine -- you'd be asking the question -- is the new solution close to the previous one? -Chris