On Tue, Jan 29, 2013 at 7:44 PM, Wolfgang Maier <wolfgang.maier@biologie.uni-freiburg.de> wrote:

list(i for i in range(100) if i<50 or stop())

Really (!) nice (and 2x as fast as using itertools.takewhile())!

I couldn't believe it so I had to check it:

from __future__ import print_function

import functools, itertools, operator, timeit

def var1():

    def _gen():

        for i in range(100):

            if i > 50: break

            yield i

    return list(_gen())

def var2():

    def stop():

        raise StopIteration

    return list(i for i in range(100) if i <= 50 or stop())

def var3():

    return [i for i in itertools.takewhile(lambda n: n <= 50, range(100))]

def var4():

    return [i for i in itertools.takewhile(functools.partial(operator.lt, 50), range(100))]

if __name__ == '__main__':

    for f in (var1, var2, var3, var4):

        print(f.__name__, end=' ')

        print(timeit.timeit(f))

Results on my machine:

var1 20.4974410534

var2 23.6218020916

var3 32.1543409824

var4 4.90913701057

var1 might have became the fastest of the first 3 because it's a special and very simple case. Why should explicit loops be slower that generator expressions?

var3 is the slowest. I guess, because it has lambda in it.

But switching to Python and back can not be faster than the last option - sitting in the C code as much as we can.

--

Kind regards, Yuriy.

_______________________________________________
Python-ideas mailing list
Python-ideas@python.org
http://mail.python.org/mailman/listinfo/python-ideas