On Fri, Jul 26, 2019 at 10:52:46AM -0400, Calvin Spealman wrote:
> Let's say you do this or any of the variants suggested... What does this do?
>
> a = {"foo": 1}
> b = {}
> with a:
> with b:
> foo = 0
Re-writing that to my suggested version:
with namespace("a") as a:
with namespace("b") as b:
foo = 0
will create a namespace object (a subclass of ModuleType) and bind it to
"a", containing a namespace object "b", containing a variable "foo":
assert isinstance(a, NamespaceType)
assert isinstance(a.b, NamespaceType)
assert a.b.foo == 0
That would be analogous to this existing code:
class a:
class b:
foo = 0
except classes have different scoping rules to modules.
--
Steven
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