-1 on the feature, I use the compound expression as below, only have the internal item be a generator expression to reduce peak memory usage. Also, the != condition is unnecessary. [t for t in (t.strip() for t in text.split('\n')) if t] Overloading 'as', 'with', etc., when there are simple expressions that already do the *exact* same thing is silly. Never mind that not everything needs to be done in a 1-liner or list comprehension. - Josiah On Wed, Aug 27, 2008 at 10:30 AM, Bruce Leban <bruce@leapyear.org> wrote:
[t for t in [t.strip() for t in text.split('\n')] if t != '']
On Wed, Aug 27, 2008 at 10:00 AM, Imri Goldberg <lorgandon@gmail.com> wrote:
+1 from me, I find myself doing that all the time as well.
On Wed, Aug 27, 2008 at 7:51 PM, Tarek Ziadé <ziade.tarek@gmail.com> wrote:
Hello
There's a pattern I am doing all the time: filtering out some elements of a list, and cleaning them in the same move.
For example, if I have a multi line text, where I want to:
- keep non empty lines - clean non empty lines
I am doing:
>>> text = """ ... this is a multi-line text\t ... ... \t\twith ... ... muliple lines."""
>>> [l.strip() for l in text.split('\n') if l.strip() != ''] ['this is a multi-line text', 'with', 'muliple lines.']
It is not optimal, because I call strip() twice. I could use ifilter then imap or even use a real loop, but I want my simple, concise, list comprehension ! And I couldn't find a simple way to express it.
The pattern can be generically resumed like this :
[transform(e) for e in seq if some_test(transform(e))]
So what about using the 'as' keyword to extend lists comprehensions, and to avoid calling transform() twice ?
Could be:
[transform(e) as transformed for e in seq if some_test(transformed)]
In my use case I would simply have to write;:
[l.strip() as stripped for l in text.split('\n') if stripped != '']
Which seems to me clear and concise.
Regards, Tarek
-- Tarek Ziadé | Association AfPy | www.afpy.org Blog FR | http://programmation-python.org Blog EN | http://tarekziade.wordpress.com/
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