On 4/23/2015 8:31 PM, MRAB wrote:
On 2015-04-24 01:15, Ethan Furman wrote:
On 04/23, Riley Banks wrote:
I propose adding the ability to compare range objects using methods (e.g. range.issubrange) and/or regular operators. Example:
In : range(0, 10, 3).issubrange(range(10)) Out: True In : range(0, 10, 3) <= range(10) Out: True
This was not obvious to me. Ranges are not sets.
In : range(10) <= range(0, 10, 3) Out: False
I seem to recall orderable ranges being rejected before. For example, is less-than, or subrange, dependent on the values themselves, or on the lowest and highest values, or on the start and end value, or ...
I remember the same. There is no intuitive answer. Let us not rehash this again.
In other words, given:
a = range(11) b = range(12, step=3)
is a < b, or b < a? Why?
It could be functionally equivalent to list(a) < list(b).
For range(0, 10, 3) <= range(10), this would give the opposite answer as the set interpretation.