Re: [Python-ideas] Adding exception logging function to syslog module.

March 23, 2010

      Eric Smith wrote:
...
I think this would be a great addition. I have to do similar things all 
of the time, although I never though of using sys.excepthook, for some 
reason. I'll have to steal your code in the meantime!
A simpler pure Python version would be:
from __future__ import print_function
def logexceptions(also_stderr=True):
    import sys
    import traceback
    import syslog
    def syslog_exception(etype, evalue, etb):
        # The result of traceback.format_exception might contain
# embedded newlines, so we have the nested loops.
for line in traceback.format_exception(etype, evalue, etb):
            for line in line.rstrip().split('\n'):
                syslog.syslog(line)
                if also_stderr:
                    print(line, file=sys.stderr)
    sys.excepthook = syslog_exception
logexceptions(True)
On second thought, maybe it would be better to optionally chain to the 
existing sys.excepthook instead of assuming it writes to stderr. The 
above code would become:

def logexceptions(chain=True):
     import sys
     import traceback
     import syslog
     current_hook = sys.excepthook
     def syslog_exception(etype, evalue, etb):
         if chain:
             current_hook(etype, evalue, etb)
         # The result of traceback.format_exception might contain 

         # embedded newlines, so we have the nested loops. 

         for line in traceback.format_exception(etype, evalue, etb):
             for line in line.rstrip().split('\n'):
                 syslog.syslog(line)
     sys.excepthook = syslog_exception

I think I'll open an issue for this. I don't think the language 
moratorium would preclude its addition.

Eric.

-- 
Eric.