Here is a very toy proof-of-concept:

>>> from vector import Vector
>>> l = "Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec".split()
>>> v = Vector(l)
>>> v
<Vector of ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec']>
>>> v.strip().lower().replace('a','X')
<Vector of ['jXn', 'feb', 'mXr', 'Xpr', 'mXy', 'jun', 'jul', 'Xug', 'sep', 'oct', 'nov', 'dec']>
>>> vt = Vector(tuple(l))
>>> vt
<Vector of ('Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec')>
>>> vt.lower().replace('o','X')
<Vector of ('jan', 'feb', 'mar', 'apr', 'may', 'jun', 'jul', 'aug', 'sep', 'Xct', 'nXv', 'dec')>

One thing I think I'd like to be different is to have some way of accessing EITHER the collection being held OR each element.  So now I just get:

>>> v.__len__()
<Vector of [3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3]>

Yes, that's an ugly spelling of `len(v)`, but let's bracket that for the moment.  It would be nice also to be able to ask "what's the length of the vector, in a non-vectorized way" (i.e. 12 in this case).  Maybe some naming convention like:

>>> v.collection__len__()
12

This last is just a possible behavior, not in the code I just uploaded.

On Sat, Feb 2, 2019 at 6:47 PM Chris Angelico <rosuav@gmail.com> wrote:
On Sun, Feb 3, 2019 at 10:36 AM Ben Rudiak-Gould <benrudiak@gmail.com> wrote:
>
> On Sat, Feb 2, 2019 at 3:23 PM Christopher Barker <pythonchb@gmail.com> wrote:
>>
>> a_list_of_strings.strip().lower().title()
>>
>> is a lot nicer than:
>>
>> [s.title() for s in (s.lower() for s in [s.strip(s) for s in a_list_of_strings])]
>>
>> or
>>
>> list(map(str.title, (map(str.lower, (map(str.strip, a_list_of_strings)))) # untested
>
> In this case you can write
>
>     [s.strip().lower().title() for s in a_list_of_strings]

What if it's a more complicated example?

len(sorted(a_list_of_strings.casefold())[:100])

where the len() is supposed to give back a list of the lengths of the
first hundred strings, sorted case insensitively? (Okay so it's a
horrible contrived example. Bear with me.)

With current syntax, this would need multiple map calls or comprehensions:

[len(s) for s in sorted(s.casefold() for s in a_list_of_strings)[:100]]

(Better examples welcomed.)

ChrisA
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