Re: [Python-ideas] "continue with" for dynamic iterable injection

25 Sep 2014

      On 25 September 2014 08:09, Cathal Garvey 
wrote:
...
The idea is that `continue with` would allow injection of any datatype
or variable, which becomes the next iterated item. So, saying `continue
with 5` means that the next *x* in a loop structured as `for x in..`
would be 5.
You can effectively do this just with generators.

def process(iterable):
    for e in iterable:
        yield e
        yield -e

for e in process([1, 2, 3]):
    print(e)

If you need to get more complex, investigate the send() method of
generators.

Tim Delaney