On Jan 22, 2016, at 11:50 PM, Andrew Barnert via Python-ideas <python-ideas@python.org> wrote:
On Jan 21, 2016, at 00:48, Victor Stinner <victor.stinner@gmail.com> wrote:
Hi,
Sorry but I'm lost in this long thread.
I think the whole issue of const optimization is taking this discussion way off track, so let me try to summarize the actual issue.
What the thread is ultimately looking for is a solution to the "closures capturing loop variables" problem. This problem has been in the official programming FAQ[1] for decades, as "Why do lambdas defined in a loop with different values all return the same result"?
powers = [lambda x: x**i for i in range(10)]
This gives you ten functions that all return x**9, which is probably not what you wanted.
The original request could have also been solved with ``functools.partial``. Sure, this is a toy solution, but the problem as originally shared was a toy problem.
from functors import partial a = 1 f = partial(lambda a,x: a+x, a) f(10) 11 a = 2 f(10) 11
Seems to me quite similar to the original suggestion from haael: """ a = 1 b = 2 c = 3 fun = lambda[a, b, c] x, y: a + b + c + x + y """