* DOC: OrderDict.values() comparisons in Python 3 * Src: https://hg.python.org/cpython/file/f2a0a4a45292/Doc/library/collections.rst#... What should it say? ```rst .. `< https://hg.python.org/cpython/file/f2a0a4a45292/Doc/library/collections.rst#...
`__
collections.OrderedDict.values().__eq__
* "is suprising"
* Python 3 has `dict views`_
* :class:`OrderedDict` matches the dict interface in Python 2.7 and
Python 3.
*
https://docs.python.org/2/library/collections.html#collections.OrderedDict
*
https://docs.python.org/3/library/collections.html#collections.OrderedDict
* Python 2 dict interface:
* dict.viewkeys(), dict.viewvalues(), dict.viewitems()
* dict.keys(), dict.values(), dict.items()
* https://docs.python.org/2/library/stdtypes.html#dict
* https://docs.python.org/2/library/stdtypes.html#dict.values
* https://docs.python.org/2/library/stdtypes.html#dictionary-view-objects
* Python 3 dict interface (:ref:`dictionary view objects`:
* dict.keys(), dict.values(), dict.items()
* list(dict.keys()), list(dict.values()), list(dict.items())
* https://docs.python.org/3/library/stdtypes.html#dict
* https://docs.python.org/3/library/stdtypes.html#dict.values
* https://docs.python.org/3/library/stdtypes.html#dictionary-view-objects
* In order to compare OrderedDict.values() **by value**
you must either:
* Cast values() to a sequence (e.g. a list) before comparison
* Subclass :class:`OrderedDict` and wrap `values()`
.. code:: python
from collections import OrderedDict
a = 'a'
x = 1
y = x
ab = [( a, x), ('b', 2)]
ba = [('b', 2), (a, y)]
ab_odict = OrderedDict(ab)
ab_odict_ = OrderedDict(ab)
ab_odict_copy = OrderedDict(ab.copy())
ba_odict = OrderedDict(ba)
ab_dict = dict(ab)
ba_dict = dict(ba)
# In Python 3,
# OrderedDict.values.__eq__ does not compare by value:
assert ( ab_odict.values() == ab_odict_.values()) is False
assert (list(ab_odict.values()) == list(ab_odict_.values()) is True
# In Python 2.7 and 3,
# OrderedDict.__eq__ compares ordered sequences
assert (ab_odict == ab_odict_) is True
assert (ab_odict == ab_odict_copy) is True
assert (ab_odict == ba_odict) is False
assert (ab_dict == ba_dict) is True
# - [ ] How to explain the x, y part?
# - in terms of references, __eq__, id(obj), __hash__
```
On Wed, Jan 20, 2016 at 12:39 PM, Sven R. Kunze
Documentation is a very good idea.
Maybe, even raise an error when comparing values.
Best, Sven
On 20.01.2016 12:13, Alexandre Figura wrote:
If we put technical considerations aside, maybe we should just ask to ourselves what behavior do we expect when doing equality tests between ordered dictionaries. As a reminder:
xy = OrderedDict([('x', None), ('y', None)]) yx = OrderedDict([('y', None), ('x', None)]) xy == yx False xy.items() == yx.items() True xy.keys() == yx.keys() True xy.values() == yx.values() False
So, it appears that: 1. equality tests between odict_values use objects identity and not equality, 2. equality tests between odict_keys do not respect order.
If it is not technically possible to change the current implementation, maybe all we can do is just add a warning about current behavior in the documentation?
On Mon, Jan 11, 2016 at 4:17 AM, Guido van Rossum <
guido@python.org> wrote: Seems like we dropped the ball... Is there any action item here?
-- --Guido van Rossum (python.org/~guido http://python.org/%7Eguido)
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